Update exercises/108_labeled_switch.zig
Fixed an error in the debug statement and made the text a bit more coherent. Signed-off-by: chrboesch <chrboesch@noreply.codeberg.org>
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1 changed files with 9 additions and 11 deletions
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@ -15,11 +15,11 @@
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// 1 => { op = 2; continue; },
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// 2 => { op = 3; continue; },
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// 3 => return,
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// 4 => {},
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// else => {},
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// }
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// break;
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// }
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// std.debug.print("This statement cannot be reached");
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// std.debug.print("This statement cannot be reached\n", .{});
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// }
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//
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// By combining all we've learned so far, we can now proceed with a labeled switch
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@ -36,23 +36,21 @@
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// 3 => return,
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// else => {},
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// }
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// std.debug.print("This statement cannot be reached");
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// std.debug.print("This statement cannot be reached\n", .{});
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// }
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//
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// The flow of execution on this second case is:
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// 1. The switch starts with value '1';
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// 2. The switch evaluates to case '1' which in turn uses the continue statement
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// to re-evaluate the labeled switch again, now providing the value '2';
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// to re-evaluate the labeled switch again, now providing the value '2';
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// 3. In the case '2' we repeat the same pattern as case '1'
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// but instead the value to be evaluated is now '3';
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// 4. Finally we get to case '3', where we return from the function as a whole.
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// but instead the value to be evaluated is now '3';
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// 4. Finally we get to case '3', where we return from the function as a whole,
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// so the debug statement is never executed.
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// 5. In this example, since the input does not have clear, exhaustive patterns and
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// can essentially be any `u8` integer, we need to handle all cases not explicitly
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// covered by using the `else => {}` branch as the default case.
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// can essentially be any 'u8' integer, we need to handle all cases not explicitly
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// covered by using the 'else => {}' branch as the default case.
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//
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// Since step 4 or a break stament do not exist in this switch, the debug statement is
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// never executed
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//
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const std = @import("std");
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